What is the solution for y^{''}+n^2y=0,y(0)=c,y^'(0)=v ?

The solution for y^{''}+n^2y=0,y(0)=c,y^'(0)=v is y=ccos(nt)+(vsin(nt))/n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+n^2y=0,y(0)=c,y^'(0)=v

y^{^{''}} + n^{2} y = 0, y (0) = c, y^{^{'}} (0) = v

y = c cos (n t) + \frac{v sin ( n t )}{n}

Solution steps

y^{''} (t) + n^{2} y = 0

Solve linear ODE:

y = c cos (n t) + \frac{v sin ( n t )}{n}

y = c cos (n t) + \frac{v sin ( n t )}{n}

4 y^{^{''}} - 8 y^{^{'}} + 3 y = 0, y (0) = 2, y^{^{'}} (0) = \frac{1}{2}

24 y^{^{''}} + 2.2 y = 0

y^{^{''}} + 30 y^{^{'}} + a y = 0

y^{^{''}} + y^{^{'}} = 0, y (0) = - 1

f^{^{''}} (t) - f^{^{'}} (t) - 2 f (t) = 0, f (0) = 1, f^{^{'}} (0) = 0

What is the solution for y^{''}+n^2y=0,y(0)=c,y^'(0)=v ?
The solution for y^{''}+n^2y=0,y(0)=c,y^'(0)=v is y=ccos(nt)+(vsin(nt))/n