What is (\partial)/(\partial x)(200(x-y^2)) ?

The answer to (\partial)/(\partial x)(200(x-y^2)) is 200

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(\partial)/(\partial x)(200(x-y^2))

\frac{\partial}{\partial x} (200 (x - y^{2}))

200

Solution steps

\frac{\partial}{\partial x} (200 (x - y^{2}))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 200 \frac{\partial}{\partial x} (x - y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 200 (\frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y^{2}))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y^{2}) = 0

= 200 (1 - 0)

Simplify

= 200

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What is (\partial)/(\partial x)(200(x-y^2)) ?
The answer to (\partial)/(\partial x)(200(x-y^2)) is 200