What is the solution for 2y^{''}-9y^'+9y=0 ?

The solution for 2y^{''}-9y^'+9y=0 is y=c_{1}e^{3t}+c_{2}e^{(3t)/2}

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2y^{''}-9y^'+9y=0

2 y^{^{''}} - 9 y^{^{'}} + 9 y = 0

y = c_{1} e^{3 t} + c_{2} e^{\frac{3 t}{2}}

Solution steps

2 y^{''} (t) - 9 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{\frac{3 t}{2}}

y = c_{1} e^{3 t} + c_{2} e^{\frac{3 t}{2}}

81 y^{^{''}} - 18 y^{^{'}} + 5 y = 0, y (1) = 1, y^{^{'}} (1) = 7

9 x^{^{''}} + 9 x^{^{'}} - 4 x = 0

x^{^{''}} = a^{2} x

y^{^{''}} + y = 0, y (π) = 1, y (0) = 1

2 y^{^{''}} - 6 y^{^{'}} + 8 y = 0

What is the solution for 2y^{''}-9y^'+9y=0 ?
The solution for 2y^{''}-9y^'+9y=0 is y=c_{1}e^{3t}+c_{2}e^{(3t)/2}