What is the solution for 9y^{''}+8y^'+7y=0 ?

The solution for 9y^{''}+8y^'+7y=0 is y=e^{-(4t)/9}(c_{1}cos((sqrt(47)t)/9)+c_{2}sin((sqrt(47)t)/9))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9y^{''}+8y^'+7y=0

9 y^{^{''}} + 8 y^{^{'}} + 7 y = 0

y = e^{- \frac{4 t}{9}} (c_{1} cos (\frac{47 t}{9}) + c_{2} sin (\frac{47 t}{9}))

Solution steps

9 y^{''} (t) + 8 y^{'} (t) + 7 y = 0

Solve linear ODE:

y = e^{- \frac{4 t}{9}} (c_{1} cos (\frac{47 t}{9}) + c_{2} sin (\frac{47 t}{9}))

y = e^{- \frac{4 t}{9}} (c_{1} cos (\frac{47 t}{9}) + c_{2} sin (\frac{47 t}{9}))

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 2, y (1) = 2

\frac{d ^{2} y}{d t ^{2}} + 7 \frac{d y}{d t} + 12 y = 0

\frac{d ^{2} y}{d t ^{2}} - 18 \frac{d y}{d t} + 145 y = 0

y^{^{'''}} - 3 y^{^{''}} - 15 y^{^{'}} + 25 y = 0

y^{^{''}} + 14 y^{^{'}} + 48 y = 0, y (0) = 0, y^{^{'}} (0) = - 6

What is the solution for 9y^{''}+8y^'+7y=0 ?
The solution for 9y^{''}+8y^'+7y=0 is y=e^{-(4t)/9}(c_{1}cos((sqrt(47)t)/9)+c_{2}sin((sqrt(47)t)/9))