What is the solution for y^{''}+5y^'+6y=0,y(0)=10,y^'(0)=0 ?

The solution for y^{''}+5y^'+6y=0,y(0)=10,y^'(0)=0 is y=30e^{-2t}-20e^{-3t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+5y^'+6y=0,y(0)=10,y^'(0)=0

y^{^{''}} + 5 y^{^{'}} + 6 y = 0, y (0) = 10, y^{^{'}} (0) = 0

y = 30 e^{- 2 t} - 20 e^{- 3 t}

Solution steps

y^{''} (t) + 5 y^{'} (t) + 6 y = 0

Solve linear ODE:

y = 30 e^{- 2 t} - 20 e^{- 3 t}

y = 30 e^{- 2 t} - 20 e^{- 3 t}

y^{^{''}} - 4 y = 0, y (0) = 6, y^{^{'}} (0) = 0

y^{^{''}} + 49 y = 0, y (0) = 2, y^{^{'}} (0) = 1

y^{^{''}} - 4 y + 3 y = 0, y (0) = - 1, y^{^{'}} (0) = - 5

\frac{1}{8} y^{^{''}} + 4 y^{^{'}} + 8 y = 0, y (0) = 0, y^{^{'}} (0) = 8

y^{^{''}} + 4 y^{^{'}} + 20 y = 0, y (0) = 6, y^{^{'}} (0) = - 11

What is the solution for y^{''}+5y^'+6y=0,y(0)=10,y^'(0)=0 ?
The solution for y^{''}+5y^'+6y=0,y(0)=10,y^'(0)=0 is y=30e^{-2t}-20e^{-3t}