What is the limit as x approaches-1 of sqrt(16-4x) ?

The limit as x approaches-1 of sqrt(16-4x) is 2sqrt(5)

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limit as x approaches-1 of sqrt(16-4x)

x \to - 1 lim (16 - 4 x)

25

Decimal Notation

4.47213 \dots

Solution steps

x \to - 1 lim (16 - 4 x)

Plug in the value

x = - 1

= 16 - 4 (- 1)

Simplify

16 - 4 (- 1) : 25

= 25

\int ((y) ln (1 + y)) d y

\int (2 + \frac{5}{7} x - 6 x^{2}) d x

\frac{d}{d x} ((x - 5) x - 5)

x \to 0 lim (\frac{( x - 1 ) ^{3} - 1}{x})

\int (\frac{2}{x} - \frac{1}{x ^{2}}) d x

What is the limit as x approaches-1 of sqrt(16-4x) ?
The limit as x approaches-1 of sqrt(16-4x) is 2sqrt(5)