What is the solution for y^{''}-y=0,y(0)=4,y^'(0)=4 ?

The solution for y^{''}-y=0,y(0)=4,y^'(0)=4 is y=4e^t

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y^{''}-y=0,y(0)=4,y^'(0)=4

y^{^{''}} - y = 0, y (0) = 4, y^{^{'}} (0) = 4

y = 4 e^{t}

Solution steps

y^{''} (t) - y = 0

Solve linear ODE:

y = 4 e^{t}

y = 4 e^{t}

y^{^{''}} - y^{^{'}} - 120 y = 0

c \cdot y^{^{''}} + y^{^{'}} = 0

\frac{d ^{2} y}{d x ^{2}} - 12 \frac{d y}{d x} + 52 y = 0

y^{^{''}} + cy = 0, y (0) = a, y^{^{'}} (0) = 0

y^{^{''}} - 3 y^{^{'}} + (2.25 + a) y = 0, y (0) = 0

What is the solution for y^{''}-y=0,y(0)=4,y^'(0)=4 ?
The solution for y^{''}-y=0,y(0)=4,y^'(0)=4 is y=4e^t