What is the solution for (d^2x)/(dt^2)+15(dx)/(dt)+56x=0 ?

The solution for (d^2x)/(dt^2)+15(dx)/(dt)+56x=0 is x=c_{1}e^{-7t}+c_{2}e^{-8t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2x)/(dt^2)+15(dx)/(dt)+56x=0

\frac{d ^{2} x}{d t ^{2}} + 15 \frac{d x}{d t} + 56 x = 0

x = c_{1} e^{- 7 t} + c_{2} e^{- 8 t}

Solution steps

\frac{d ^{2} x}{d t ^{2}} + 15 \frac{d x}{d t} + 56 x = 0

Solve linear ODE:

x = c_{1} e^{- 7 t} + c_{2} e^{- 8 t}

x = c_{1} e^{- 7 t} + c_{2} e^{- 8 t}

4 f (x) = f^{^{''}} (x)

y^{^{''}} + 6 y^{^{'}} = 0, y (0) = - 4, y^{^{'}} (0) = 6

y^{^{''}} = 7 y^{^{'}} - 10 y, y (0) = 0, y^{^{'}} (0) = - 3

\frac{1}{4} y^{^{''}} + 3 y^{^{'}} + 4 y = 0

y^{^{''}} + 6 y + 90 y = 0

What is the solution for (d^2x)/(dt^2)+15(dx)/(dt)+56x=0 ?
The solution for (d^2x)/(dt^2)+15(dx)/(dt)+56x=0 is x=c_{1}e^{-7t}+c_{2}e^{-8t}