What is the solution for y^{''}+(49)/(4/32)y=0 ?

The solution for y^{''}+(49)/(4/32)y=0 is y=c_{1}cos(14sqrt(2)t)+c_{2}sin(14sqrt(2)t)

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y^{''}+(49)/(4/32)y=0

y^{^{''}} + \frac{49}{\frac{4}{32}} y = 0

y = c_{1} cos (142 t) + c_{2} sin (142 t)

Solution steps

y^{''} (t) + \frac{49}{\frac{4}{32}} y = 0

Solve linear ODE:

y = c_{1} cos (142 t) + c_{2} sin (142 t)

y = c_{1} cos (142 t) + c_{2} sin (142 t)

y^{^{''}} + 9 y = 0, y^{^{'}} (3 π) = 9, y (0) = 9

(y^{^{''}}) + 9 y = 0

2 y^{^{''}} + 3 y^{^{'}} - 2 y = 0, y (0) = 1, y (0) = 7

2 y^{^{''}} + 9 y^{^{'}} + 8 y = 0, y (0) = 5, y^{^{'}} (0) = 0

\frac{d ^{2} x}{d t ^{2}} + 2 a \frac{d x}{d t} + b^{2} x = 0, a < b

What is the solution for y^{''}+(49)/(4/32)y=0 ?
The solution for y^{''}+(49)/(4/32)y=0 is y=c_{1}cos(14sqrt(2)t)+c_{2}sin(14sqrt(2)t)