What is the solution for (d^3y)/(dt^3)-(d^2y)/(dt^2)=0 ?

The solution for (d^3y)/(dt^3)-(d^2y)/(dt^2)=0 is y=c_{1}e^t+c_{2}+c_{3}t

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(d^3y)/(dt^3)-(d^2y)/(dt^2)=0

\frac{d ^{3} y}{d t ^{3}} - \frac{d ^{2} y}{d t ^{2}} = 0

y = c_{1} e^{t} + c_{2} + c_{3} t

Solution steps

\frac{d ^{3} y}{d t ^{3}} - \frac{d ^{2} y}{d t ^{2}} = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} + c_{3} t

y = c_{1} e^{t} + c_{2} + c_{3} t

y^{^{''}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = \frac{18}{5}

64 y^{^{''}} + 16 y^{^{'}} + 50 y = 0

x^{^{''}} - (nπ)^{2} x = 0

y^{^{''}} - 3 y^{^{'}} - 4 y = 0

3 y^{^{''}} + 2 y^{^{'}} - y = 0, y (0) = 1, y^{^{'}} (0) = - 3

What is the solution for (d^3y)/(dt^3)-(d^2y)/(dt^2)=0 ?
The solution for (d^3y)/(dt^3)-(d^2y)/(dt^2)=0 is y=c_{1}e^t+c_{2}+c_{3}t