What is the solution for 1/y y^{''}=a ?

The solution for 1/y y^{''}=a is y=c_{1}e^{sqrt(a)t}+c_{2}e^{-sqrt(a)t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/y y^{''}=a

\frac{1}{y} y^{^{''}} = a

y = c_{1} e^{a t} + c_{2} e^{- a t}

Solution steps

\frac{1}{y} y^{''} (t) = a

Solve linear ODE:

y = c_{1} e^{a t} + c_{2} e^{- a t}

y = c_{1} e^{a t} + c_{2} e^{- a t}

y^{^{''}} - y = 0, y (- 1) = 9, y^{^{'}} (- 1) = - 9

y^{^{'''}} - y^{^{''}} + 9 y^{^{'}} - 145 y = 0, y (0) = e^{5 x}

f^{^{''}} (x) - f^{^{'}} (x) - 2 f (x) = 0, f (0) = 2

100 (1 0^{- 6}) y^{^{''}} + \frac{1}{500} y^{^{'}} + y = 0

y^{^{''}} + 3 y = 0, y^{^{'}} (1) = 1

What is the solution for 1/y y^{''}=a ?
The solution for 1/y y^{''}=a is y=c_{1}e^{sqrt(a)t}+c_{2}e^{-sqrt(a)t}