What is the solution for y^{''}+9y^'+14y=0,y(0)=0,y^'(0)=-1 ?

The solution for y^{''}+9y^'+14y=0,y(0)=0,y^'(0)=-1 is y=-1/5 e^{-2t}+1/5 e^{-7t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+9y^'+14y=0,y(0)=0,y^'(0)=-1

y^{^{''}} + 9 y^{^{'}} + 14 y = 0, y (0) = 0, y^{^{'}} (0) = - 1

y = - \frac{1}{5} e^{- 2 t} + \frac{1}{5} e^{- 7 t}

Solution steps

y^{''} (t) + 9 y^{'} (t) + 14 y = 0

Solve linear ODE:

y = - \frac{1}{5} e^{- 2 t} + \frac{1}{5} e^{- 7 t}

y = - \frac{1}{5} e^{- 2 t} + \frac{1}{5} e^{- 7 t}

y^{^{''}} + 10 y^{^{'}} + 25 y = 0, y (0) = 2, y^{^{'}} (0) = - 9

y^{^{''}} - y^{^{'}} - 12 y = 0, y (0) = 2, y^{^{'}} (0) = - 3

5 y^{^{'}} + 6 y^{^{''}} = 0

y^{^{''}} - 400 y = 0

y^{^{''}} + (1 + a) y = 0

What is the solution for y^{''}+9y^'+14y=0,y(0)=0,y^'(0)=-1 ?
The solution for y^{''}+9y^'+14y=0,y(0)=0,y^'(0)=-1 is y=-1/5 e^{-2t}+1/5 e^{-7t}