What is the solution for 2y^{''}-5y^'-3y=3y ?

The solution for 2y^{''}-5y^'-3y=3y is y=c_{1}e^{((5+sqrt(73))t)/4}+c_{2}e^{((5-sqrt(73))t)/4}

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2y^{''}-5y^'-3y=3y

2 y^{^{''}} - 5 y^{^{'}} - 3 y = 3 y

y = c_{1} e^{\frac{( 5 + 73 ) t}{4}} + c_{2} e^{\frac{( 5 - 73 ) t}{4}}

Solution steps

2 y^{''} (t) - 5 y^{'} (t) - 3 y = 3 y

Solve linear ODE:

y = c_{1} e^{\frac{( 5 + 73 ) t}{4}} + c_{2} e^{\frac{( 5 - 73 ) t}{4}}

y = c_{1} e^{\frac{( 5 + 73 ) t}{4}} + c_{2} e^{\frac{( 5 - 73 ) t}{4}}

10000 y^{^{''}} - 81 y^{^{'}} = 0, y (0) = 8, y^{^{'}} (0) = 5

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 8, y (1) = 0

\frac{d ^{2} y}{d x ^{2}} - \frac{11}{2} \frac{d y}{d x} + 6 y = 0

y^{^{'''}} - 27 y = 0

(D^{2} - 6 D + 9) y = 0

What is the solution for 2y^{''}-5y^'-3y=3y ?
The solution for 2y^{''}-5y^'-3y=3y is y=c_{1}e^{((5+sqrt(73))t)/4}+c_{2}e^{((5-sqrt(73))t)/4}