What is the tangent of f(x)=(5x-9)(x+5),(2,7) ?

The tangent of f(x)=(5x-9)(x+5),(2,7) is y=36x-65

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tangent of f(x)=(5x-9)(x+5),(2,7)

tangent of

f (x) = (5 x - 9) (x + 5), (2, 7)

y = 36 x - 65

Solution steps

Find the slope of

f (x) = (5 x - 9) (x + 5) : \frac{df ( x )}{d x} = 10 x + 16

Compute the slope of

f (x) = (5 x - 9) (x + 5)

(2, 7) : m = 36

Find the line with slope m=

36

and passing through

(2, 7) : y = 36 x - 65

y = 36 x - 65

x^{^{''}} + 10 x^{^{'}} + 21 x = 0

\int \frac{x + 10}{x ^{2} - x - 2} d x

\int_{- 3}^{0} (9 - x^{2}) d x

\frac{\partial}{\partial x} (7 y^{6} x^{6} - 6 y^{5} x^{5})

y d x + (x - 4) d y = 0

What is the tangent of f(x)=(5x-9)(x+5),(2,7) ?
The tangent of f(x)=(5x-9)(x+5),(2,7) is y=36x-65