What is the solution for y^{''}+14y^'+51y=0 ?

The solution for y^{''}+14y^'+51y=0 is y=e^{-7t}(c_{1}cos(sqrt(2)t)+c_{2}sin(sqrt(2)t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+14y^'+51y=0

y^{^{''}} + 14 y^{^{'}} + 51 y = 0

y = e^{- 7 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

Solution steps

y^{''} (t) + 14 y^{'} (t) + 51 y = 0

Solve linear ODE:

y = e^{- 7 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

y = e^{- 7 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

y^{^{'''}} - 4 y^{^{''}} - 5 y^{^{'}} = 0, y (1) = 0, y^{^{'}} (1) = 8

y^{^{''}} - 1 y^{^{'}} + 0.1 y = 0

(d^{4} - 1) y = 0

y^{^{''}} - 6 y^{^{'}} + 5 y = 0, y (0) = 1, y (1) = 3

4 y^{^{''}} - 2 y^{^{'}} - 2 y = 0, y (0) = 2, y^{^{'}} (0) = 1

What is the solution for y^{''}+14y^'+51y=0 ?
The solution for y^{''}+14y^'+51y=0 is y=e^{-7t}(c_{1}cos(sqrt(2)t)+c_{2}sin(sqrt(2)t))