What is the solution for u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=-7 ?

The solution for u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=-7 is u(t)=integral of integral of-49\H(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=-7

u^{^{''}} + 49 H (t) = 0, u^{^{'}} (0) = - 7

u (t) = \int\int - 49 H (t) d t d t

Solution steps

u^{''} (t) + 49 H (t) = 0

Isolate

u^{''} (t) : u^{''} (t) = - 49 H (t)

Solve

u^{''} (t) = - 49 H (t) : u^{'} (t) = \int - 49 H (t) d t

Solve

u^{'} (t) = \int - 49 H (t) d t : u (t) = \int \int - 49 H (t) d t d t

u (t) = \int \int - 49 H (t) d t d t

y^{^{'''}} - 6 y^{^{''}} + 11 y^{^{'}} - 6 y = 0, y (π) = 0

y^{^{''}} + y = 0, y^{^{''}} (0) = 0, y (0) = 1

4 y^{^{''}} - 4 y + 5 y = 0, y (0) = \frac{1}{2}, y^{^{'}} (0) = 1

y^{^{''}} - 10 y^{^{'}} - 16 y = 0

y^{^{'}} + y = y^{^{''}}

What is the solution for u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=-7 ?
The solution for u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=-7 is u(t)=integral of integral of-49\H(t)