What is the solution for -2y^{''}-2*pi^2y=0 ?

The solution for -2y^{''}-2*pi^2y=0 is y=c_{1}cos(pit)+c_{2}sin(pit)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-2y^{''}-2*pi^2y=0

- 2 y^{^{''}} - 2 \cdot π^{2} y = 0

y = c_{1} cos (π t) + c_{2} sin (π t)

Solution steps

- 2 y^{''} (t) - 2 \cdot π^{2} y = 0

Solve linear ODE:

y = c_{1} cos (π t) + c_{2} sin (π t)

y = c_{1} cos (π t) + c_{2} sin (π t)

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (0) = 4, y^{^{'}} (0) = 1

\frac{d ^{2} x}{d t ^{2}} - 2 \frac{d x}{d t} - 15 x = 0

\frac{d ^{2} y}{d t ^{2}} - 20 \frac{d y}{d t} + 100 y = 0

y^{^{''}} - 10 y^{^{'}} - 171 y = 0, y (0) = 9, y^{^{'}} (0) = 3

y^{^{''}} - 19 y^{^{'}} - 10 y = 0, y (0) = 1, y^{^{'}} (0) = - 1

What is the solution for -2y^{''}-2*pi^2y=0 ?
The solution for -2y^{''}-2*pi^2y=0 is y=c_{1}cos(pit)+c_{2}sin(pit)