What is 2u^{''}+3/5 u^'+30\H(t)=0 ?

The answer to 2u^{''}+3/5 u^'+30\H(t)=0 is 2*0+3/5*0+30\H(t(x))=0

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2u^{''}+3/5 u^'+30\H(t)=0

2 u^{''} + \frac{3}{5} u^{'} + 30 H (t (x)) = 0

2 \cdot 0 + \frac{3}{5} \cdot 0 + 30 H (t (x)) = 0

Solution steps

2 u^{''} + \frac{3}{5} u^{'} + 30 H (t (x)) = 0

u^{''} = 0

2 \cdot 0 + \frac{3}{5} u^{^{'}} + 30 H (t (x)) = 0

u^{'} = 0

2 \cdot 0 + \frac{3}{5} \cdot 0 + 30 H (t (x)) = 0

49 y^{^{''}} - 112 y^{^{'}} + 64 y = 0

- \frac{d ^{2} y}{d x ^{2}} + 400 y = 0

y^{^{''}} + 4 y - 5 y = 0

y^{^{''}} - 2 y = 0, y (0) = 1, y^{^{'}} (0) = 6

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (0) = - 1, y^{^{'}} (0) = - \frac{9}{4}

What is 2u^{''}+3/5 u^'+30\H(t)=0 ?
The answer to 2u^{''}+3/5 u^'+30\H(t)=0 is 2*0+3/5*0+30\H(t(x))=0