What is the solution for y^{''}+0y^'+9y=0,y(0)=2,y^'(0)=0 ?

The solution for y^{''}+0y^'+9y=0,y(0)=2,y^'(0)=0 is y=2cos(3t)

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y^{''}+0y^'+9y=0,y(0)=2,y^'(0)=0

y^{^{''}} + 0 y^{^{'}} + 9 y = 0, y (0) = 2, y^{^{'}} (0) = 0

y = 2 cos (3 t)

Solution steps

y^{''} (t) + 0 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = 2 cos (3 t)

y = 2 cos (3 t)

y^{^{''}} + 2 y^{^{'}} - 15 y = 0, y (0) = 1

5 y^{^{''}} + 20 y = 0, y (\frac{π}{4}) = 10, y (0) = 15

2 y^{^{''}} + 6 y^{^{'}} = 0

y^{^{''}} + c^{2} y = 0, y (0) = a, y^{^{'}} (0) = 0

x^{^{''}} + 10 x^{^{'}} + 29 x = 0, x^{^{'}} (0) = 6

What is the solution for y^{''}+0y^'+9y=0,y(0)=2,y^'(0)=0 ?
The solution for y^{''}+0y^'+9y=0,y(0)=2,y^'(0)=0 is y=2cos(3t)