What is the derivative of 3t-4t^2 ?

The derivative of 3t-4t^2 is 3-8t

What is the first derivative of 3t-4t^2 ?

The first derivative of 3t-4t^2 is 3-8t

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derivative of

3 t - 4 t^{2}

3 - 8 t

Solution steps

\frac{d}{d t} (3 t - 4 t^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (3 t) - \frac{d}{d t} (4 t^{2})

\frac{d}{d t} (3 t) = 3

\frac{d}{d t} (4 t^{2}) = 8 t

= 3 - 8 t

\frac{d y}{d x} y = cos^{- 1} (\frac{1}{x})

(3.4) (- 6.4)

x \to 0 - lim (ln (x^{8}))

\frac{8}{x ^{2} + 4}

\int 9 x sec (x) tan (x) d x

What is the derivative of 3t-4t^2 ?
The derivative of 3t-4t^2 is 3-8t
What is the first derivative of 3t-4t^2 ?
The first derivative of 3t-4t^2 is 3-8t