What is the solution for y^{''}+y^'=0,y(pi/3)=0,y^'(pi/3)=2 ?

The solution for y^{''}+y^'=0,y(pi/3)=0,y^'(pi/3)=2 is y=2-2e^{pi/3-t}

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y^{''}+y^'=0,y(pi/3)=0,y^'(pi/3)=2

y^{^{''}} + y^{^{'}} = 0, y (\frac{π}{3}) = 0, y^{^{'}} (\frac{π}{3}) = 2

y = 2 - 2 e^{\frac{π}{3} - t}

Solution steps

y^{''} (t) + y^{'} (t) = 0

Solve linear ODE:

y = 2 - 2 e^{\frac{π}{3} - t}

y = 2 - 2 e^{\frac{π}{3} - t}

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 3

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 0

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 1

6 y^{^{''}} - y^{^{'}} + 2 y = 0

y^{^{''}} + 25 y = 0, y^{1} (0) = e^{5} x

What is the solution for y^{''}+y^'=0,y(pi/3)=0,y^'(pi/3)=2 ?
The solution for y^{''}+y^'=0,y(pi/3)=0,y^'(pi/3)=2 is y=2-2e^{pi/3-t}