What is the solution for u^{''}=\H(t) ?

The solution for u^{''}=\H(t) is u(t)=integral of integral of \H(t)

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u^{''}=\H(t)

u^{^{''}} = H (t)

u (t) = \int\int H (t) d t d t

Solution steps

u^{''} (t) = H (t)

Solve

u^{''} (t) = H (t) : u^{'} (t) = \int H (t) d t

Solve

u^{'} (t) = \int H (t) d t : u (t) = \int \int H (t) d t d t

u (t) = \int \int H (t) d t d t

0.25 \cdot 0.04 x^{^{''}} + 2 \cdot 0.04 x^{^{'}} + x = 0

y^{^{''}} + 20 y^{^{'}} + 92 y = 0

x^{^{''}} + 3 x^{^{'}} + 2 x = 0, x (0) = 0, x^{^{'}} (0) = 0

33 y^{^{''''}} + 23 y^{^{''}} + 4 y = 0

y^{^{''}} - 6 y^{^{'}} + 10 y = 0, y (π) = 1, y^{^{'}} (π) = 2

What is the solution for u^{''}=\H(t) ?
The solution for u^{''}=\H(t) is u(t)=integral of integral of \H(t)