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Popular >

(D^2-2D+1)y=0

Solution

(D^{2} - 2 D + 1) y = 0

Solution

y = c_{1} e^{x} + c_{2} x e^{x}

Solution steps

(D^{2} - 2 D + 1) y = 0

Solve linear ODE:

y = c_{1} e^{x} + c_{2} x e^{x}

y = c_{1} e^{x} + c_{2} x e^{x}

Popular Examples

y^{''}-y^'-10y=0

y^{^{''}} - y^{^{'}} - 10 y = 0

x^{^{''}} = - b x^{^{'}}

(d^2y)/(dx^2)-0.15y=0

\frac{d ^{2} y}{d x ^{2}} - 0.15 y = 0

y^{''}-15y^'+50y=0,y(0)=11,y^'(0)=-65

y^{^{''}} - 15 y^{^{'}} + 50 y = 0, y (0) = 11, y^{^{'}} (0) = - 65

y^{'''}+15y^{''}+57y^'+43y=0

y^{^{'''}} + 15 y^{^{''}} + 57 y^{^{'}} + 43 y = 0

Frequently Asked Questions (FAQ)

What is the solution for (D^2-2D+1)y=0 ?
The solution for (D^2-2D+1)y=0 is y=c_{1}e^x+c_{2}xe^x