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Popular >

1/4 y^{''}+y=0

Solution

\frac{1}{4} y^{^{''}} + y = 0

Solution

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Solution steps

\frac{1}{4} y^{''} (t) + y = 0

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t)

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Popular Examples

y^{''}+y^'+3y=0,y(0)=0

y^{^{''}} + y^{^{'}} + 3 y = 0, y (0) = 0

81y^{''}+36y^'+4y=0

81 y^{^{''}} + 36 y^{^{'}} + 4 y = 0

y*y^{''}+(y)^2=0,y(0)=4,y^'(0)=6

y \cdot y^{^{''}} + (y)^{2} = 0, y (0) = 4, y^{^{'}} (0) = 6

y^{''}+y^'-20y=0,y(0)=-3,y^'(0)=33

y^{^{''}} + y^{^{'}} - 20 y = 0, y (0) = - 3, y^{^{'}} (0) = 33

y^{''}-y^'+2y=0,y(0)=5

y^{^{''}} - y^{^{'}} + 2 y = 0, y (0) = 5

Frequently Asked Questions (FAQ)

What is the solution for 1/4 y^{''}+y=0 ?
The solution for 1/4 y^{''}+y=0 is y=c_{1}cos(2t)+c_{2}sin(2t)