What is (\partial)/(\partial y)(x^4-3x^2y) ?

The answer to (\partial)/(\partial y)(x^4-3x^2y) is -3x^2

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(\partial)/(\partial y)(x^4-3x^2y)

\frac{\partial}{\partial y} (x^{4} - 3 x^{2} y)

- 3 x^{2}

Solution steps

\frac{\partial}{\partial y} (x^{4} - 3 x^{2} y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{4}) - \frac{\partial}{\partial y} (3 x^{2} y)

\frac{\partial}{\partial y} (x^{4}) = 0

\frac{\partial}{\partial y} (3 x^{2} y) = 3 x^{2}

= 0 - 3 x^{2}

Simplify

= - 3 x^{2}

\int \frac{y ^{2}}{x ^{2}} d x

\frac{8 x ^{5} - 15}{x ^{4}}

\frac{1}{( x ^{2} + 1 )}

\frac{d y}{d x} = 8 x^{3} e^{- 2 y}

\frac{d}{d x} ((1 + tan (2 x))^{3})

What is (\partial)/(\partial y)(x^4-3x^2y) ?
The answer to (\partial)/(\partial y)(x^4-3x^2y) is -3x^2