What is the solution for u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=7 ?

The solution for u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=7 is u(t)=integral of integral of-49\H(t)

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u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=7

u^{^{''}} + 49 H (t) = 0, u^{^{'}} (0) = 7

u (t) = \int\int - 49 H (t) d t d t

Solution steps

u^{''} (t) + 49 H (t) = 0

Isolate

u^{''} (t) : u^{''} (t) = - 49 H (t)

Solve

u^{''} (t) = - 49 H (t) : u^{'} (t) = \int - 49 H (t) d t

Solve

u^{'} (t) = \int - 49 H (t) d t : u (t) = \int \int - 49 H (t) d t d t

u (t) = \int \int - 49 H (t) d t d t

24 y^{^{''}} + 14 y^{^{'}} - 3 y = 0

y^{^{''}} + 5 \cdot y^{^{'}} + a \cdot y = 0, y (0) = 1, y^{^{'}} (0) = 7

5 y^{^{''}} + c y^{^{'}} + 45 y = 0, y (0) = - 8, y^{^{'}} (0) = 0

x^{^{''}} + 12 x^{^{'}} + 27 x = 0

(d^{5} - d^{3}) \cdot y = 0

What is the solution for u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=7 ?
The solution for u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=7 is u(t)=integral of integral of-49\H(t)