What is the solution for -y^{''}+9*pi^2y=0 ?

The solution for -y^{''}+9*pi^2y=0 is y=c_{1}e^{3pit}+c_{2}e^{-3pit}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-y^{''}+9*pi^2y=0

- y^{^{''}} + 9 \cdot π^{2} y = 0

y = c_{1} e^{3 π t} + c_{2} e^{- 3 π t}

Solution steps

- y^{''} (t) + 9 \cdot π^{2} y = 0

Solve linear ODE:

y = c_{1} e^{3 π t} + c_{2} e^{- 3 π t}

y = c_{1} e^{3 π t} + c_{2} e^{- 3 π t}

y^{^{''}} + 4 y = 0, y (0) = cos (2 x)

(y^{^{''}} + 2 y^{^{'}} + 5 y)^{3} = 0

5 y^{^{''}} + 3 y^{^{'}} + 9 y = 0

y^{^{''}} - 22 y^{^{'}} + 2 y = 0

1 y^{^{''}} + 10 y^{^{'}} + \frac{32}{10} y = 0

What is the solution for -y^{''}+9*pi^2y=0 ?
The solution for -y^{''}+9*pi^2y=0 is y=c_{1}e^{3pit}+c_{2}e^{-3pit}