What is the solution for 4000y^{''}-9y^'=0 ?

The solution for 4000y^{''}-9y^'=0 is y=c_{1}e^{(9t)/(4000)}+c_{2}

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4000y^{''}-9y^'=0

4000 y^{^{''}} - 9 y^{^{'}} = 0

y = c_{1} e^{\frac{9 t}{4000}} + c_{2}

Solution steps

4000 y^{''} (t) - 9 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} e^{\frac{9 t}{4000}} + c_{2}

y = c_{1} e^{\frac{9 t}{4000}} + c_{2}

y^{^{''}} + b y^{^{'}} + 6 y = 0, y (0) = 1, y^{^{'}} (0) = 0

x^{^{''}} + 64 x^{^{'}} = 0

3 \frac{d ^{2} y}{d x ^{2}} - 14 \frac{d y}{d x} - 5 y = 0

9 y^{^{''}} - 16 y^{^{'}} = 0

y^{^{'}} + y^{^{''}} = y^{^{'''}}

What is the solution for 4000y^{''}-9y^'=0 ?
The solution for 4000y^{''}-9y^'=0 is y=c_{1}e^{(9t)/(4000)}+c_{2}