What is the solution for y^{''}-11y+18y=0 ?

The solution for y^{''}-11y+18y=0 is y=c_{1}cos(sqrt(7)t)+c_{2}sin(sqrt(7)t)

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y^{''}-11y+18y=0

y^{^{''}} - 11 y + 18 y = 0

y = c_{1} cos (7 t) + c_{2} sin (7 t)

Solution steps

y^{''} (t) - 11 y + 18 y = 0

Solve linear ODE:

y = c_{1} cos (7 t) + c_{2} sin (7 t)

y = c_{1} cos (7 t) + c_{2} sin (7 t)

y^{^{''}} + v y^{^{'}} = 0

2 x^{^{''}} + 11 x^{^{'}} + 5 x = 0

3 u^{^{''}} + 38 u^{^{'}} + 144 H (t) = 0

y^{^{''}} - 5 y^{^{'}} + 6 y = 0, y (0) = - 1, y^{^{'}} (0) = - \frac{7}{2}

y^{^{''''}} + 18 y^{^{''}} - 81 y = 0

What is the solution for y^{''}-11y+18y=0 ?
The solution for y^{''}-11y+18y=0 is y=c_{1}cos(sqrt(7)t)+c_{2}sin(sqrt(7)t)