What is the derivative of 1/(x^2+1/x) ?

The derivative of 1/(x^2+1/x) is -2/(x^3)-1/(x^2)

What is the first derivative of 1/(x^2+1/x) ?

The first derivative of 1/(x^2+1/x) is -2/(x^3)-1/(x^2)

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\frac{d}{d x} (\frac{1}{x ^{2}} + \frac{1}{x})

- \frac{2}{x ^{3}} - \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{2}} + \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{x ^{2}}) + \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= - \frac{2}{x ^{3}} - \frac{1}{x ^{2}}

\int 6 sin^{2} (x) cos^{2} (x) d x

n = 1 \sum \infty \frac{3}{2 n}

\frac{\partial}{\partial x} (e^{x + 2 y})

(ln (x^{2} + 8 x + 21))^{^{'}}

\frac{d}{d x} ((2 x)^{- 3 x})

What is the derivative of 1/(x^2+1/x) ?
The derivative of 1/(x^2+1/x) is -2/(x^3)-1/(x^2)
What is the first derivative of 1/(x^2+1/x) ?
The first derivative of 1/(x^2+1/x) is -2/(x^3)-1/(x^2)