What is the solution for y^{''}+100y=0,y(pi)=5,y(0)=2 ?

The solution for y^{''}+100y=0,y(pi)=5,y(0)=2 is y=5cos(10t)+c_{2}sin(10t)

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y^{''}+100y=0,y(pi)=5,y(0)=2

y^{^{''}} + 100 y = 0, y (π) = 5, y (0) = 2

y = 5 cos (10 t) + c_{2} sin (10 t)

Solution steps

y^{''} (t) + 100 y = 0

Solve linear ODE:

y = 5 cos (10 t) + c_{2} sin (10 t)

y = 5 cos (10 t) + c_{2} sin (10 t)

y^{^{'''}} + 9 y^{^{'}} = 0, y (0) = 7

2 y^{^{''}} - 13 y^{^{'}} + 15 y = 0, y (0) = 0, y^{^{'}} (0) = 17.5

θ^{^{''}} (t) + \frac{9. 8 ^{2}}{80} θ (t) = 0

\frac{( \frac{d ^{2} f}{d x ^{2}} )}{f ( x )} = 1

y^{^{''}} = - 4 y, y (0) = 3, y^{^{'}} (0) = - 63

What is the solution for y^{''}+100y=0,y(pi)=5,y(0)=2 ?
The solution for y^{''}+100y=0,y(pi)=5,y(0)=2 is y=5cos(10t)+c_{2}sin(10t)