What is the solution for y^{''}+y=0,y(pi/3)=2 ?

The solution for y^{''}+y=0,y(pi/3)=2 is y=(4-sqrt(3)c_{2})cos(t)+c_{2}sin(t)

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y^{''}+y=0,y(pi/3)=2

y^{^{''}} + y = 0, y (\frac{π}{3}) = 2

y = (4 - 3 c_{2}) cos (t) + c_{2} sin (t)

Solution steps

y^{''} (t) + y = 0

Solve linear ODE:

y = (4 - 3 c_{2}) cos (t) + c_{2} sin (t)

y = (4 - 3 c_{2}) cos (t) + c_{2} sin (t)

9 y^{^{''}} + 24 y^{^{'}} - 33 y = 0

\frac{d ^{2} y}{d x ^{2}} = (4 y)

y^{^{''}} + 6 y^{^{'}} + 13 y = 0, y (0) = 3, y^{^{'}} (0) = 1

y^{^{'''}} + 3 y^{^{''}} + 4 y^{^{'}} + 12 y = 0

y^{^{''}} + 4 y^{^{'}} + 5 y = 0

What is the solution for y^{''}+y=0,y(pi/3)=2 ?
The solution for y^{''}+y=0,y(pi/3)=2 is y=(4-sqrt(3)c_{2})cos(t)+c_{2}sin(t)