What is the solution for 5y^{''}-11y^'+2y=0,y(0)=-5,y^'(0)=-6.4 ?

The solution for 5y^{''}-11y^'+2y=0,y(0)=-5,y^'(0)=-6.4 is y=-3e^{2t}-2e^{t/5}

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5y^{''}-11y^'+2y=0,y(0)=-5,y^'(0)=-6.4

5 y^{^{''}} - 11 y^{^{'}} + 2 y = 0, y (0) = - 5, y^{^{'}} (0) = - 6.4

y = - 3 e^{2 t} - 2 e^{\frac{t}{5}}

Solution steps

5 y^{''} (t) - 11 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = - 3 e^{2 t} - 2 e^{\frac{t}{5}}

y = - 3 e^{2 t} - 2 e^{\frac{t}{5}}

y^{^{''}} + 6 y^{^{'}} + 8 y = 0, y (0) = - 6, y^{^{'}} (0) = 18

y 4 + 3 y^{^{''}} + y = 0

y^{^{''}} + \frac{8}{100} y^{^{'}} + \frac{12}{10000} y = 0

y^{^{''}} - y = 0, y (ln (2)) = 5, y (0) = 1

\frac{d ^{2} x}{d t ^{2}} + 4 \frac{d x}{d t} + 2 x = 0, x (0) = 0

What is the solution for 5y^{''}-11y^'+2y=0,y(0)=-5,y^'(0)=-6.4 ?
The solution for 5y^{''}-11y^'+2y=0,y(0)=-5,y^'(0)=-6.4 is y=-3e^{2t}-2e^{t/5}