What is the derivative of arccos(x)+x ?

The derivative of arccos(x)+x is -1/(sqrt(1-x^2))+1

What is the first derivative of arccos(x)+x ?

The first derivative of arccos(x)+x is -1/(sqrt(1-x^2))+1

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derivative of

arccos (x) + x

- \frac{1}{1 - x ^{2}} + 1

Solution steps

\frac{d}{d x} (arccos (x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (arccos (x)) + \frac{d x}{d x}

\frac{d}{d x} (arccos (x)) = - \frac{1}{1 - x ^{2}}

\frac{d x}{d x} = 1

= - \frac{1}{1 - x ^{2}} + 1

\int \frac{1}{( 3 sin ( x ) - 4 cos ( x ) )} d x

\frac{d}{d n} (ln (n + 1))

\int \frac{6}{( x - 4 ) ^{3}} d x

\frac{\partial}{\partial x} (3 x^{2} y + 6 x y^{3})

n = 2 \sum \infty e^{\frac{1}{n}}

What is the derivative of arccos(x)+x ?
The derivative of arccos(x)+x is -1/(sqrt(1-x^2))+1
What is the first derivative of arccos(x)+x ?
The first derivative of arccos(x)+x is -1/(sqrt(1-x^2))+1