What is the solution for (d^2y)/(dx^2)-5(dy)/(dx)-6y=0 ?

The solution for (d^2y)/(dx^2)-5(dy)/(dx)-6y=0 is y=c_{1}e^{6x}+c_{2}e^{-x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)-5(dy)/(dx)-6y=0

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} - 6 y = 0

y = c_{1} e^{6 x} + c_{2} e^{- x}

Solution steps

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} - 6 y = 0

Solve linear ODE:

y = c_{1} e^{6 x} + c_{2} e^{- x}

y = c_{1} e^{6 x} + c_{2} e^{- x}

y^{^{''}} + 8 y^{^{'}} + 16 y = 0, y (- 1) = 2, y^{^{'}} (- 1) = 4

y^{^{''}} + 8 y^{^{'}} + 16 y = 0, y (- 1) = 2, y^{^{'}} (- 1) = 2

x^{^{''}} + 10 x^{^{'}} + 16 x = 0, x (0) = 1, x^{^{'}} (0) = - 13

4 y^{^{''}} + 8 y^{^{'}} - 21 y = 0

6 y^{^{''}} - 5 y^{^{'}} + y = 0, y (0) = e^{\frac{x}{2}}

What is the solution for (d^2y)/(dx^2)-5(dy)/(dx)-6y=0 ?
The solution for (d^2y)/(dx^2)-5(dy)/(dx)-6y=0 is y=c_{1}e^{6x}+c_{2}e^{-x}