What is the derivative of (14+5x-3x^2^{3/4}) ?

The derivative of (14+5x-3x^2^{3/4}) is (3(-6x+5))/(4(14+5x-3x^2)^{1/4)}

What is the first derivative of (14+5x-3x^2^{3/4}) ?

The first derivative of (14+5x-3x^2^{3/4}) is (3(-6x+5))/(4(14+5x-3x^2)^{1/4)}

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\frac{d}{d x} ((14 + 5 x - 3 x^{2})^{\frac{3}{4}})

\frac{3 ( - 6 x + 5 )}{4 ( 14 + 5 x - 3 x ^{2} ) ^{\frac{1}{4}}}

Solution steps

\frac{d}{d x} ((14 + 5 x - 3 x^{2})^{\frac{3}{4}})

Apply the chain rule:

\frac{3}{4 ( 14 + 5 x - 3 x ^{2} ) ^{\frac{1}{4}}} \frac{d}{d x} (14 + 5 x - 3 x^{2})

= \frac{3}{4 ( 14 + 5 x - 3 x ^{2} ) ^{\frac{1}{4}}} \frac{d}{d x} (14 + 5 x - 3 x^{2})

\frac{d}{d x} (14 + 5 x - 3 x^{2}) = - 6 x + 5

= \frac{3}{4 ( 14 + 5 x - 3 x ^{2} ) ^{\frac{1}{4}}} (- 6 x + 5)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 ( - 6 x + 5 )}{4 ( 14 + 5 x - 3 x ^{2} ) ^{\frac{1}{4}}}

\frac{d}{d x} (x^{2} sin^{8} (x) + x cos^{- 6} (x))

\int_{0}^{2 π} 6 x^{2} sin (\frac{x}{4}) d x

\frac{\partial}{\partial x} (e^{x yz} tan (x + 2 y + z))

x sin (\frac{2}{x})

y = 4 x^{3} + x, x = 2, x = - 1, x

What is the derivative of (14+5x-3x^2^{3/4}) ?
The derivative of (14+5x-3x^2^{3/4}) is (3(-6x+5))/(4(14+5x-3x^2)^{1/4)}
What is the first derivative of (14+5x-3x^2^{3/4}) ?
The first derivative of (14+5x-3x^2^{3/4}) is (3(-6x+5))/(4(14+5x-3x^2)^{1/4)}