What is the solution for y^{''}-6y^'+9y=0,y(0)=-4,y^'(0)=-28/3 ?

The solution for y^{''}-6y^'+9y=0,y(0)=-4,y^'(0)=-28/3 is y=-4e^{3t}+(8e^{3t}t)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-6y^'+9y=0,y(0)=-4,y^'(0)=-28/3

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = - 4, y^{^{'}} (0) = - \frac{28}{3}

y = - 4 e^{3 t} + \frac{8 e ^{3 t} t}{3}

Solution steps

y^{''} (t) - 6 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = - 4 e^{3 t} + \frac{8 e ^{3 t} t}{3}

y = - 4 e^{3 t} + \frac{8 e ^{3 t} t}{3}

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = 2, y^{^{'}} (0) = 3.65

y^{^{''}} + 2 y^{^{'}} = 0, y (0) = - 3, y^{^{'}} (0) = 12

y^{^{'''}} - 4 y^{^{'}} - 5 y^{^{'}} = 0

0.5 x^{^{''}} + 0.5 x^{^{'}} + 6 x = 0, x (0) = 3, x^{^{'}} (0) = 0

324 y^{^{''}} + 396 y^{^{'}} + 121 y = 0

What is the solution for y^{''}-6y^'+9y=0,y(0)=-4,y^'(0)=-28/3 ?
The solution for y^{''}-6y^'+9y=0,y(0)=-4,y^'(0)=-28/3 is y=-4e^{3t}+(8e^{3t}t)/3