What is the solution for y^{''}+2y^'=0,y(0)=14,y^'(0)=-10 ?

The solution for y^{''}+2y^'=0,y(0)=14,y^'(0)=-10 is y=5e^{-2t}+9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+2y^'=0,y(0)=14,y^'(0)=-10

y^{^{''}} + 2 y^{^{'}} = 0, y (0) = 14, y^{^{'}} (0) = - 10

y = 5 e^{- 2 t} + 9

Solution steps

y^{''} (t) + 2 y^{'} (t) = 0

Solve linear ODE:

y = 5 e^{- 2 t} + 9

y = 5 e^{- 2 t} + 9

y^{^{''}} - 14 y^{^{'}} + 85 y = 0, y (0) = 2, y^{^{'}} (0) = - 4

x^{^{''}} - 2 a x^{^{'}} + a^{2} x = 0

14 y^{^{''}} + 3 y^{^{'}} - 2 y = 0

y^{^{''}} - 4 y^{^{'}} + 4 y = 0, y (0) = 0, y^{^{'}} (0) = 3

y^{^{''}} + 0.6 y^{^{'}} + 8 y = 0

What is the solution for y^{''}+2y^'=0,y(0)=14,y^'(0)=-10 ?
The solution for y^{''}+2y^'=0,y(0)=14,y^'(0)=-10 is y=5e^{-2t}+9