What is the solution for y^{''}+220/55 y=0 ?

The solution for y^{''}+220/55 y=0 is y=c_{1}cos(2t)+c_{2}sin(2t)

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y^{''}+220/55 y=0

y^{^{''}} + \frac{220}{55} y = 0

y = c_{1} cos (2 t) + c_{2} sin (2 t)

Solution steps

y^{''} (t) + \frac{220}{55} y = 0

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t)

y = c_{1} cos (2 t) + c_{2} sin (2 t)

y^{^{''}} + 16 y = 0, y (0) = 2, y^{^{''}} (0) = - 2

y^{^{'''}} + y^{^{''}} - 16 y^{^{'}} + 20 y = 0

3 y^{^{''}} + 5 y^{^{'}} + y = 0

y^{^{''}} + 16 y = 0, y (0) = 3, y^{^{'}} (0) = 1

y^{^{''}} + 16 y = 0, y (0) = 3, y^{^{'}} (0) = 0

What is the solution for y^{''}+220/55 y=0 ?
The solution for y^{''}+220/55 y=0 is y=c_{1}cos(2t)+c_{2}sin(2t)