What is the solution for u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7 ?

The solution for u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7 is u(t)=integral of integral of-7\H(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7

u^{^{''}} + 7 H (t) = 0, u^{^{'}} (0) = 7

u (t) = \int\int - 7 H (t) d t d t

Solution steps

u^{''} (t) + 7 H (t) = 0

Isolate

u^{''} (t) : u^{''} (t) = - 7 H (t)

Solve

u^{''} (t) = - 7 H (t) : u^{'} (t) = \int - 7 H (t) d t

Solve

u^{'} (t) = \int - 7 H (t) d t : u (t) = \int \int - 7 H (t) d t d t

u (t) = \int \int - 7 H (t) d t d t

y^{^{''}} + 4 y^{^{'}} + 13 y^{^{'}} = 0

y \cdot α + \frac{d ^{2} y}{d x ^{2}} = 0

4 y^{^{''}} - 4 y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (0) = 1

y^{^{''}} - 5 y^{^{'}} - 2 a^{2} y = 0

x^{^{''}} + 2 \cdot b \cdot x^{^{'}} + x = 0, x (0) = 1, x^{^{'}} (0) = - 1

What is the solution for u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7 ?
The solution for u^{''}+7\H(t)=0,\H(0)=0,u^'(0)=7 is u(t)=integral of integral of-7\H(t)