What is the solution for x^{''}+80x=0 ?

The solution for x^{''}+80x=0 is x=c_{1}cos(4sqrt(5)t)+c_{2}sin(4sqrt(5)t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{''}+80x=0

x^{^{''}} + 80 x = 0

x = c_{1} cos (45 t) + c_{2} sin (45 t)

Solution steps

x^{''} (t) + 80 x = 0

Solve linear ODE:

x = c_{1} cos (45 t) + c_{2} sin (45 t)

x = c_{1} cos (45 t) + c_{2} sin (45 t)

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (0) = - 2, y (0) = - 14

2 y^{^{''}} + 18 y = 0, y (0) = 2, y^{^{'}} (0) = 15

y^{^{'''''}} + 20 y^{^{'''}} = 0

\frac{5}{8} x^{^{''}} + 40 x = 0, x (0) = \frac{1}{3}, x^{^{'}} (0) = 0

y^{^{''}} - 2 y^{^{'}} - 8 y = 0, y (0) = a, y^{^{'}} (0) = 10

What is the solution for x^{''}+80x=0 ?
The solution for x^{''}+80x=0 is x=c_{1}cos(4sqrt(5)t)+c_{2}sin(4sqrt(5)t)