What is the derivative of-(2x/((x^2+3)^2)) ?

The derivative of-(2x/((x^2+3)^2)) is -(6(-x^2+1))/((x^2+3)^3)

What is the first derivative of-(2x/((x^2+3)^2)) ?

The first derivative of-(2x/((x^2+3)^2)) is -(6(-x^2+1))/((x^2+3)^3)

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\frac{d}{d x} (- \frac{2 x}{( x ^{2} + 3 ) ^{2}})

- \frac{6 ( - x ^{2} + 1 )}{( x ^{2} + 3 ) ^{3}}

Solution steps

\frac{d}{d x} (- \frac{2 x}{( x ^{2} + 3 ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (\frac{x}{( x ^{2} + 3 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 2 \cdot \frac{\frac{d x}{d x} ( x ^{2} + 3 ) ^{2} - \frac{d}{d x} ( ( x ^{2} + 3 ) ^{2} ) x}{( ( x ^{2} + 3 ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((x^{2} + 3)^{2}) = 4 x (x^{2} + 3)

= - 2 \cdot \frac{1 \cdot ( x ^{2} + 3 ) ^{2} - 4 x ( x ^{2} + 3 ) x}{( ( x ^{2} + 3 ) ^{2} ) ^{2}}

Simplify

- 2 \cdot \frac{1 \cdot ( x ^{2} + 3 ) ^{2} - 4 x ( x ^{2} + 3 ) x}{( ( x ^{2} + 3 ) ^{2} ) ^{2}} : - \frac{6 ( - x ^{2} + 1 )}{( x ^{2} + 3 ) ^{3}}

= - \frac{6 ( - x ^{2} + 1 )}{( x ^{2} + 3 ) ^{3}}

x \to 0 + lim (\frac{8 x}{sin ( x )})

x \to - 3 lim (∣ x + 3 ∣)

x \to 0 - lim (e^{\frac{1}{x}} + 1)

(\frac{1}{y ^{2}} - \frac{6}{y ^{4}}) (y + 4 y^{3})

x \to 3 lim (I n (x - 3))

What is the derivative of-(2x/((x^2+3)^2)) ?
The derivative of-(2x/((x^2+3)^2)) is -(6(-x^2+1))/((x^2+3)^3)
What is the first derivative of-(2x/((x^2+3)^2)) ?
The first derivative of-(2x/((x^2+3)^2)) is -(6(-x^2+1))/((x^2+3)^3)