What is the solution for y^{''}+7y^'=0,y(0)=-1,y^'(0)=-35 ?

The solution for y^{''}+7y^'=0,y(0)=-1,y^'(0)=-35 is y=5e^{-7t}-6

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y^{''}+7y^'=0,y(0)=-1,y^'(0)=-35

y^{^{''}} + 7 y^{^{'}} = 0, y (0) = - 1, y^{^{'}} (0) = - 35

y = 5 e^{- 7 t} - 6

Solution steps

y^{''} (t) + 7 y^{'} (t) = 0

Solve linear ODE:

y = 5 e^{- 7 t} - 6

y = 5 e^{- 7 t} - 6

c \frac{d ^{2} y}{d x ^{2}} = y

2 x^{^{''}} + 72 x = 0

y^{^{''}} - 10 y^{^{'}} + 25 y = 0, y (0) = 6, y^{^{'}} (0) = 25

y^{^{''}} + 1 y^{^{'}} + y = 0

y^{^{''}} + u^{2} y = 0, y^{^{'}} (\frac{π}{2}) = 0, y (0) = 0

What is the solution for y^{''}+7y^'=0,y(0)=-1,y^'(0)=-35 ?
The solution for y^{''}+7y^'=0,y(0)=-1,y^'(0)=-35 is y=5e^{-7t}-6