What is the solution for y^{''}-6y^'+9y=0,y(0)=4,y^'(0)=-1 ?

The solution for y^{''}-6y^'+9y=0,y(0)=4,y^'(0)=-1 is y=4e^{3t}-13e^{3t}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-6y^'+9y=0,y(0)=4,y^'(0)=-1

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 4, y^{^{'}} (0) = - 1

y = 4 e^{3 t} - 13 e^{3 t} t

Solution steps

y^{''} (t) - 6 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = 4 e^{3 t} - 13 e^{3 t} t

y = 4 e^{3 t} - 13 e^{3 t} t

y^{^{''}} - r^{2} y = 0

\frac{5}{32} y^{^{''}} + \frac{1}{4} y = 0

4 \frac{d ^{2} y}{d x ^{2}} - y = 0

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 2, y^{^{'}} (0) = 7

y^{^{'''}} + 13 y^{^{''}} + 43 y^{^{'}} + 31 y = 0

What is the solution for y^{''}-6y^'+9y=0,y(0)=4,y^'(0)=-1 ?
The solution for y^{''}-6y^'+9y=0,y(0)=4,y^'(0)=-1 is y=4e^{3t}-13e^{3t}t