What is the solution for 9y^{''}-12y^'+4y=0,y(0)=2,y(0)=3 ?

The solution for 9y^{''}-12y^'+4y=0,y(0)=2,y(0)=3 is y=2e^{(2t)/3}+c_{2}e^{(2t)/3}t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9y^{''}-12y^'+4y=0,y(0)=2,y(0)=3

9 y^{^{''}} - 12 y^{^{'}} + 4 y = 0, y (0) = 2, y (0) = 3

y = 2 e^{\frac{2 t}{3}} + c_{2} e^{\frac{2 t}{3}} t

Solution steps

9 y^{''} (t) - 12 y^{'} (t) + 4 y = 0

Solve linear ODE:

y = 2 e^{\frac{2 t}{3}} + c_{2} e^{\frac{2 t}{3}} t

y = 2 e^{\frac{2 t}{3}} + c_{2} e^{\frac{2 t}{3}} t

x^{^{''}} = - 2 x^{^{'}}

y^{^{''}} - 4 y^{^{'}} + 3 y = 0, y (1) x = e^{3 x}

y^{^{''}} + 10 y^{^{'}} + 25 y = 0, y (- 1) = 6, y^{^{'}} (- 1) = 5

y^{^{''}} + 10 y^{^{'}} + 25 y = 0, y (- 1) = 6, y^{^{'}} (- 1) = 4

y^{^{''}} + y^{^{'}} - 2 y = 0, y^{^{'}} (0) = 1

What is the solution for 9y^{''}-12y^'+4y=0,y(0)=2,y(0)=3 ?
The solution for 9y^{''}-12y^'+4y=0,y(0)=2,y(0)=3 is y=2e^{(2t)/3}+c_{2}e^{(2t)/3}t