What is (\partial)/(\partial x)(y^3cos(3x)*3) ?

The answer to (\partial)/(\partial x)(y^3cos(3x)*3) is -9y^3sin(3x)

Popular >

(\partial)/(\partial x)(y^3cos(3x)*3)

\frac{\partial}{\partial x} (y^{3} cos (3 x) \cdot 3)

- 9 y^{3} sin (3 x)

Solution steps

\frac{\partial}{\partial x} (y^{3} cos (3 x) \cdot 3)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y^{3} \cdot 3 \frac{\partial}{\partial x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{\partial}{\partial x} (3 x)

= - sin (3 x) \frac{\partial}{\partial x} (3 x)

\frac{\partial}{\partial x} (3 x) = 3

= y^{3} \cdot 3 (- sin (3 x) \cdot 3)

Simplify

= - 9 y^{3} sin (3 x)

\frac{d}{d x} (e^{x} + e^{- x} - 2)

\int_{0}^{2} \frac{2 t}{( t - 3 ) ^{2}} d t

\frac{\partial}{\partial x} (\frac{9 x - 2 y}{9 x + 2 y})

f (x) = \frac{x ^{\frac{1}{3}} - 4}{x ^{\frac{7}{2}}}

c \cdot sin (\frac{π x}{L})

What is (\partial)/(\partial x)(y^3cos(3x)*3) ?
The answer to (\partial)/(\partial x)(y^3cos(3x)*3) is -9y^3sin(3x)