What is the solution for 2y^{''}+5y^'+3y=0,y(0)=1,y^'(0)=-1.5 ?

The solution for 2y^{''}+5y^'+3y=0,y(0)=1,y^'(0)=-1.5 is y=e^{-(3t)/2}

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2y^{''}+5y^'+3y=0,y(0)=1,y^'(0)=-1.5

2 y^{^{''}} + 5 y^{^{'}} + 3 y = 0, y (0) = 1, y^{^{'}} (0) = - 1.5

y = e^{- \frac{3 t}{2}}

Solution steps

2 y^{''} (t) + 5 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = e^{- \frac{3 t}{2}}

y = e^{- \frac{3 t}{2}}

4 y^{^{''}} + y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = - 1

y^{^{''}} + 13 y^{^{'}} = 0

x^{^{''}} + x^{^{'}} + 1000 x = 0

y^{^{''}} + 14 y^{^{'}} + 50 y = 0, y (0) = - 5, y^{^{'}} (0) = 5

v^{^{''}} + 3 v^{^{'}} + 2 v = 0

What is the solution for 2y^{''}+5y^'+3y=0,y(0)=1,y^'(0)=-1.5 ?
The solution for 2y^{''}+5y^'+3y=0,y(0)=1,y^'(0)=-1.5 is y=e^{-(3t)/2}