What is the solution for y^{''}-2y^'-143y=0,y(0)=12,y^'(0)=-12 ?

The solution for y^{''}-2y^'-143y=0,y(0)=12,y^'(0)=-12 is y=5e^{13t}+7e^{-11t}

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y^{''}-2y^'-143y=0,y(0)=12,y^'(0)=-12

y^{^{''}} - 2 y^{^{'}} - 143 y = 0, y (0) = 12, y^{^{'}} (0) = - 12

y = 5 e^{13 t} + 7 e^{- 11 t}

Solution steps

y^{''} (t) - 2 y^{'} (t) - 143 y = 0

Solve linear ODE:

y = 5 e^{13 t} + 7 e^{- 11 t}

y = 5 e^{13 t} + 7 e^{- 11 t}

2 y^{^{''}} + 7 y^{^{'}} + 3 y = 0, y^{^{'}} (0) = 0, y (0) = 3

y^{^{''}} - 6 y^{^{'}} + 13 y = 0, y (0) = e^{3} x cos (2 x)

y^{^{''}} = \frac{( a - 2 )}{a} y

16 y^{^{''}} - 32 y^{^{'}} + 65 y = 0

4 y^{^{''}} + 5 y^{^{'}} - 6 y = 0

What is the solution for y^{''}-2y^'-143y=0,y(0)=12,y^'(0)=-12 ?
The solution for y^{''}-2y^'-143y=0,y(0)=12,y^'(0)=-12 is y=5e^{13t}+7e^{-11t}