What is the solution for y^{'''}-y^{''}+9y^'-9y=0 ?

The solution for y^{'''}-y^{''}+9y^'-9y=0 is y=c_{1}e^t+c_{2}cos(3t)+c_{3}sin(3t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{'''}-y^{''}+9y^'-9y=0

y^{^{'''}} - y^{^{''}} + 9 y^{^{'}} - 9 y = 0

y = c_{1} e^{t} + c_{2} cos (3 t) + c_{3} sin (3 t)

Solution steps

y^{'''} (t) - y^{''} (t) + 9 y^{'} (t) - 9 y = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} cos (3 t) + c_{3} sin (3 t)

y = c_{1} e^{t} + c_{2} cos (3 t) + c_{3} sin (3 t)

y^{^{''}} - 12 y^{^{'}} + 136 y = 0

256 y^{^{''''}} = 16 y

y^{^{''}} - 7 y^{^{'}} - 4 y = 0

y^{^{''}} - 15 y^{^{'}} + 50 y = 0, y (0) = 8, y^{^{'}} (0) = - 55

y^{^{''}} + 10 y^{^{'}} + \frac{8}{3} y = 0, y (0) = 0, y^{^{'}} (0) = - 5

What is the solution for y^{'''}-y^{''}+9y^'-9y=0 ?
The solution for y^{'''}-y^{''}+9y^'-9y=0 is y=c_{1}e^t+c_{2}cos(3t)+c_{3}sin(3t)