What is the solution for y^{''}+6y^'+73y=0,y(0)=-5,y^'(0)=-25 ?

The solution for y^{''}+6y^'+73y=0,y(0)=-5,y^'(0)=-25 is y=e^{-3t}(-5cos(8t)-5sin(8t))

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y^{''}+6y^'+73y=0,y(0)=-5,y^'(0)=-25

y^{^{''}} + 6 y^{^{'}} + 73 y = 0, y (0) = - 5, y^{^{'}} (0) = - 25

y = e^{- 3 t} (- 5 cos (8 t) - 5 sin (8 t))

Solution steps

y^{''} (t) + 6 y^{'} (t) + 73 y = 0

Solve linear ODE:

y = e^{- 3 t} (- 5 cos (8 t) - 5 sin (8 t))

y = e^{- 3 t} (- 5 cos (8 t) - 5 sin (8 t))

y^{^{'''}} = - 3 y^{^{''}} + y^{^{'}}

y^{^{''''}} - y = 0, y (0) = 2

0.0650400000000 \dots f (x) = \frac{d ^{2} f}{d x ^{2}}

y^{^{''}} + 6 y^{^{'}} = 0, y (0) = 2, y^{^{'}} (0) = 42

2 y^{^{''}} + 35 y = 0, y (0) = 7, y^{^{'}} (0) = 9

What is the solution for y^{''}+6y^'+73y=0,y(0)=-5,y^'(0)=-25 ?
The solution for y^{''}+6y^'+73y=0,y(0)=-5,y^'(0)=-25 is y=e^{-3t}(-5cos(8t)-5sin(8t))